![]() ![]() Once you hit land, you'll want to head to the north side of the island, where you'll find a glowing butterfly which flutters to and from three strange silver canisters sticking out of the ground. Welcome to episode 2 of my Agent Jones challenges In this second video, we investigate an anomaly detected on Shark Island to unlock the Jump 23 style.Epi. It's surrounded by a large wall that you can't break through, so. ![]() It's found in the northwest corner of the island, north of Coral Castle. Investigate an Anomaly in Stealthy Stronghold Stealthy Stronghold is located at the north or slightly northwest end of the map. This unnamed location is still quite obvious once you see it in person, as it features a rock formation that looks like a shark opening its jaws. Naturally, you'll first want to land on Shark Island. Investigate an Anomaly Detected on Shark Island Location - FortniteFor one of the Special Quest challenges in Fortnite Battle Royale Chapter 2 Season 6 you n. How to Investigate an Anomaly on Shark Island Smash the wall in front of the bear to reveal a secret room housing a peculiar glass display table adorned with empty jewel slots. Investigate an Anomaly Locations in Fortnite Season 6: Shark The anomalies can be found at Shark Island, Catty Corner, Lazy Lake, Weeping Wood. ![]() Here's where to find and how to investigate the Shark Island Anomaly in Fortnite Season 6. This particular challenge and associated puzzle becomes available once you hit Battle Pass level 28. Here's what you need to know to solve the Shark Island Anomaly puzzle.įortnite Season 6 is teasing players with new Anomaly puzzles, like the Shark Island Anomaly players encounter once they progress far enough in the Season 6 Battle Pass. Fortnite Guide: Investigate An Anomaly On Shark IslandĪnother Fortnite anomaly has appeared on Shark Island. Unlike other Anomaly puzzles, such as the Anomaly in Lazy Lake, the Anomaly on Shark Island, or the Anomaly near Catty Corner, this fourth Anomaly isn't so much a puzzle as it is a chase. ![]()
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